10-28-2011 at 07:40 PM
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#1
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Math 1b03 project 1
hey
if anyone wants to work together on math 1b03 project one give me a shout =)
I hate electricity x_x
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10-30-2011 at 07:35 PM
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#2
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I'm not posting here 'cause I want to work together, but because I want to discuss the project. >__>
1) The prof said any online tool was acceptable, right?
2) Q5, what IS that form? Do we have to make it into a state vector or something?
I'm so confused.
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10-30-2011 at 10:42 PM
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#3
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Quote:
Originally Posted by Faer
I'm not posting here 'cause I want to work together, but because I want to discuss the project. >__>
1) The prof said any online tool was acceptable, right?
2) Q5, what IS that form? Do we have to make it into a state vector or something?
I'm so confused.
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1) I'm pretty sure any online tool is fine; I've been using Wolfram Alpha.
2) Say the first row of your RREF matrix was:
1 0 0 0 0 -5 | 6
If I6=t, then in x0+tx1 form, I1=6+5t. Except you're doing this for all of the rows, so it might be more like:
[column vector I]=[column vector B]+t[column vector corresponding to I6]
I'm not really sure if that makes sense, but it's hard to show with just typing. Let me know if you need me to be clearer about anything.
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Honours Chemistry '15
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10-31-2011 at 12:07 AM
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#4
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Oooooh, that makes so much sense, thank you!
My equations are probably not right, then, because what I get is...um, I get a perfect RREF. Like, every variable is equal to a number. :/
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10-31-2011 at 04:44 AM
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#5
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Quote:
Originally Posted by Bug324
1) I'm pretty sure any online tool is fine; I've been using Wolfram Alpha.
2) Say the first row of your RREF matrix was:
1 0 0 0 0 -5 | 6
If I6=t, then in x0+tx1 form, I1=6+5t. Except you're doing this for all of the rows, so it might be more like:
[column vector I]=[column vector B]+t[column vector corresponding to I6]
I'm not really sure if that makes sense, but it's hard to show with just typing. Let me know if you need me to be clearer about anything.
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WOW, I feel dumb! Everything else took me 5-15 minutes per question...
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Honours Biochemistry III
Nintendo 3DS Friend Code: 2723-8915-0978
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10-31-2011 at 09:12 AM
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#6
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Heh, same. I was cruising along until I was like WHAAAAAAAT. xD
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10-31-2011 at 10:54 AM
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#7
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Quote:
Originally Posted by Faer
Oooooh, that makes so much sense, thank you!
My equations are probably not right, then, because what I get is...um, I get a perfect RREF. Like, every variable is equal to a number. :/
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You're welcome!
I also had a unique solution the first time I did it. Double-check your equations for sure, that's probably it.
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10-31-2011 at 11:30 AM
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#8
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Awesome, thanks.  |
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10-31-2011 at 03:49 PM
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#9
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for the first question we should have 7 equations right? I have 10 o_o.
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10-31-2011 at 03:57 PM
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#10
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O________________O
7. First go node by node (current in = current out). Then go closed loop by closed loop. LOL, hope that helps!
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10-31-2011 at 03:59 PM
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#11
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Loops
-I2(10) + 400 – I1(10) = 0
I1(10) – 400 +I5(20) + I4(10) + I3(20) = 0
-I4(10) + I6(R) = 0
I3(20) – I2(10) + I5(20) + I4(10) = 0
I1(10) - 400 + I5(20) + I6(R) +I3(20) = 0
-I2(10) +I5(20) + I6(R) +I3(20) = 0
Nodes
I1 = I2 + I3
I3 = I4 + I6
I4 + I6 = I5
I5 + I2 = I1
Am I doing this totally wrong?
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10-31-2011 at 04:32 PM
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#12
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Hey!
I have it as:
Loops:
10I1+10I2=400
10I1+2I3+10I4+20I5=40 0
10I4-RI6=0
Nodes:
I1-I2-I3 = 0
I3-I4-I6=0
I4+I6-I5=0
I5+I2-I1=0
I'm on question 6 now. I have my R value and I solved I6 to be 10/R(I4). The problem is, when I go to sub that into my parameterized equations, I can't solve for t. Does anybody know where I'm going wrong?
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10-31-2011 at 05:05 PM
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#13
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Brit, how did you get that? did you only divide the circuit into 3?
also, if you row reduce the "nodes", you remove an equation =o
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10-31-2011 at 05:10 PM
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#14
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finally get it >.< finally can get past the first question
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10-31-2011 at 07:42 PM
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#15
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did anyone else get something over 11 for the final column and the 3rd last column? (when in row reduced form)
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